Author Topic: command tran (transient)  (Read 8748 times)

johnh

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command tran (transient)
« on: September 27, 2012, 01:01:17 AM »
Hello,

In the 8.2 manual, it says that the default option of the "tran" is off (please look at the captured image of the manual).
Is the default is "off"?

Secondly, if I set

order 0 0 0
tran

then, does it activate dynamic or static calculation?

Thanks,
John

Prof. R.L. Taylor

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Re: command tran (transient)
« Reply #1 on: September 27, 2012, 06:53:54 AM »
One way to check what happens is to look at the 'output' file.  There you will find that it says that Newmark is activated, however, when the solution enters the routine it will check the value of the 'order' for each dof and perform an appropriate update.  Look in 'dyna01.f' in the program directory.  There you will see that it looks at
'ndo(i)' for each 'i' dof -- this is the order value.  The updates are only done for non-zero values.  Hence, what is the answer to your question?

You should always set up a small problem (one element will do) and test what the commands give.  You can check by hand if the solution is 'static', or 'transient'.  This is always a user's responsibility -- every computer program has 'bugs' or 'mistakes'.  Doing a small problem can help identify these so we can correct or provide documentation on performance.


johnh

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Re: command tran (transient)
« Reply #2 on: October 01, 2012, 10:17:42 PM »
Dear Professor Taylor,

Now, the solution flow is clear to me.
Thank you so much for your help and advice.

Best wishes,
John

Prof. R.L. Taylor

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Re: command tran (transient)
« Reply #3 on: October 08, 2012, 11:09:12 AM »
Do a one element (use a truss element with only 1-dof active).  You can then test all the options and check by hand the result.